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150x-x^2=1200
We move all terms to the left:
150x-x^2-(1200)=0
We add all the numbers together, and all the variables
-1x^2+150x-1200=0
a = -1; b = 150; c = -1200;
Δ = b2-4ac
Δ = 1502-4·(-1)·(-1200)
Δ = 17700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{17700}=\sqrt{100*177}=\sqrt{100}*\sqrt{177}=10\sqrt{177}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-10\sqrt{177}}{2*-1}=\frac{-150-10\sqrt{177}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+10\sqrt{177}}{2*-1}=\frac{-150+10\sqrt{177}}{-2} $
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